Question : If the diagonals of a rhombus are 8 cm and 6 cm, then the square of its side is:
Option 1: $25\;\mathrm{cm^2}$
Option 2: $55\;\mathrm{cm^2}$
Option 3: $64\;\mathrm{cm^2}$
Option 4: $36\;\mathrm{cm^2}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $25\;\mathrm{cm^2}$
Solution : The square of the side length, $s^2= \frac{d_1^2 + d_2^2}{4}$, where $d_1$ and $d_2$ are the diagonals of a rhombus. ⇒ The square of the side length of the rhombus $=\frac{8^2 + 6^2}{4} = \frac{64 + 36}{4} =25\;\mathrm{cm^2}$ Hence, the correct answer is $25\;\mathrm{cm^2}$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The parallel sides of a trapezium are $8\;\mathrm{cm}$ and $4\;\mathrm{cm}$. If the $\mathrm{M}$ and $\mathrm{N}$ are the mid-points of the diagonals of the trapezium, then the length of $\mathrm{MN}$ is:
Question : The diagonals of a rhombus are 12 cm and 16 cm, respectively. The length of one side is:
Question : If the side of an equilateral triangle is 16 cm, then what is its area?
Question : In an equilateral triangle ABC, D is the midpoint of side BC. If the length of BC is 8 cm, then the height of the triangle is:
Question : The length of each side of a triangle is 12 cm. What is the length of the circumradius of the triangle?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile