Question : If the height of the cylinder is increased by 35% and the radius is increased by 10%, what will be the percentage increase in the curved surface area of a cylinder?
Option 1: 46.5
Option 2: 45
Option 3: 48.5
Option 4: 49.7
Correct Answer: 48.5
Solution : Let, original height = $h$ Original radius = $r$ So, the Curved surface area of the cylinder = $2\pi r h $ After 35% increase, height = $h+h\times \frac{35}{100}=1.35h$ After 10% increase, radius = $r+r\times\frac{10}{100}=1.1r$ So, the new curved surface area of the cylinder = $2\pi \times1.1r\times 1.35h=2.97\pi rh$ Hence, percentage increase = $\frac{2.97\pi rh-2\pi rh}{2\pi rh}\times100=48.5\%$ Hence, the correct answer is 48.5.
Answer Key | Eligibility | Application | Selection Process | Result | Cutoff | Admit Card
Question : Which of the following statements is not correct?
Question : What is the radius of a normal cylinder whose height is 21 cm and curved surface area is 1386 cm2?
Question : What is the curved surface area (in cm2) of a cylinder having a radius of base as 14 cm and height as 10 cm?
Question : If the radius of a circle is increased by 10%, what will be the percentage increase in the area of the circle?
Question : A cylinder of height 8 cm and radius 6 cm is melted and converted into three cones of the same radius and height of the cylinder. Determine the total curved surface area of cones.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile