20 Views

Question : If the length of each of two equal sides of an isosceles triangle is 10 cm and the adjacent angle is $45^{\circ}$, then the area of the triangle is:

Option 1: $20\sqrt{2}$ sq. cm

Option 2: $12\sqrt{2}$ sq. cm

Option 3: $25\sqrt{2}$ sq. cm

Option 4: $15\sqrt{2}$ sq. cm


Team Careers360 5th Jan, 2024
Answer (1)
Team Careers360 16th Jan, 2024

Correct Answer: $25\sqrt{2}$ sq. cm


Solution :
$AD = AB \sin 45^\circ$
$= 10\times\frac{1}{\sqrt2}$
$= 5\sqrt2$ cm
$\therefore$ Area of $\triangle ABC = \frac{1}{2}\times BC \times AD$
$=\frac{1}{2}\times 10 \times 5\sqrt2$
$= 25\sqrt2$ sq. cm
Hence, the correct answer is $25\sqrt2$ sq. cm.

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books