If the line 2x+y-1=0,x-3y+k=0 are concurrent then k=
Answer (1)
16th Oct, 2020
Hello there!
Lines are concurrent if they pass through a common point.
In order to find the value of k we have to find the value of x and y where both lines intersect.
Since, there are 3 variables (x,y and k) and we have only 2 equations. In this case, we can only find the value of k in terms of x or y.
Here is the approach:-
2x+y-1 = 0 ….eqn (1)
x-3y+k = 0 ….eqn (2)
Multiplying eqn (2) by 2 we get,
2x-6y+2k = 0 …eqn (3)
Subtracting eqn (1) from eqn (3) we get,
-7y+2k+1 = 0
From the above equation we get,
k = (7y-1)/2
Hope this answer resolves your query.
Comments (0)
