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if the minor axis of an ellipse is equal to the distance between its foci the eccentricity is


kcharan.7353 29th Dec, 2020
Answer (1)
Heena GJ 29th Dec, 2020

Hello

If minor axis of an ellipse is equal to the distance between it's foci the eccentricity is 1/ square root of 2

Distance between the foci  2 ae

Length of the minor axis = 2b

2ae =2b

ae= b

b square = a square (1-e square)

a2e2=a2-a2e2

2 a2e2 = a2

e2= 1/2

Hence e = 1/√2

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29th Dec, 2020
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29th Dec, 2020
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29th Dec, 2020
Did u can say in other ways
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