if the minor axis of an ellipse is equal to the distance between its foci the eccentricity is
Answer (1)
29th Dec, 2020
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If minor axis of an ellipse is equal to the distance between it's foci the eccentricity is 1/ square root of 2
Distance between the foci 2 ae
Length of the minor axis = 2b
2ae =2b
ae= b
b square = a square (1-e square)
a2e2=a2-a2e2
2 a2e2 = a2
e2= 1/2
Hence e = 1/√2
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