Hi Aspirant!
As we all know,
Mole fraction of solute + mole fraction of solvent = 1
In aqueous solution of NaOH, solute is NaOH (sodium hydroxide) and solvent is water (H2O). In the question given above it is mentioned that mole fraction of NaOH (solute) is 0.2
By the equation written above,
0.2 + mole fraction of solvent (water) = 1
Therefore, mole fraction of solvent = 1- 0.2
And, thus, mole fraction of solvent is 0.8 (option d)
Thankyou
Question : What is the value of $\frac{1.2 \times 1.2+0.2 \times 0.2+1.2 \times 0.4}{1.8 \times 1.8+0.4 \times 0.4-1.8 \times 0.8} ?$
Option 1: 0.1
Option 2: 0.25
Option 3: 0.2
Option 4: 1
Question : What is the value of $\frac{0.1 \div 0.2 \times 0.3+0.4 \times 0.5 \div 0.1}{0.1 \times 0.2-0.01} ?$
Option 1: 220
Option 2: 210
Option 3: 216
Option 4: 215
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