If the mole fraction of NaOH in its aqueous solution is 0.2 then mole fraction of solvent will be a).0.2 b).0.4 c).0.1 d).0.8
Answer (1)
Student Expert
28th Jan, 2021
Hi Aspirant!
As we all know,
Mole fraction of solute + mole fraction of solvent = 1
In aqueous solution of NaOH, solute is NaOH (sodium hydroxide) and solvent is water (H2O). In the question given above it is mentioned that mole fraction of NaOH (solute) is 0.2
By the equation written above,
0.2 + mole fraction of solvent (water) = 1
Therefore, mole fraction of solvent = 1- 0.2
And, thus, mole fraction of solvent is 0.8 (option d)
Thankyou
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Comments (1)
Concentrated aqueous sulphuric acid is 49%H2SO4 (w/w) and has a density of 1.80 g/ ml. molarity of solution is
a ).1
b ).1.8
c ).18
d). 9
a ).1
b ).1.8
c ).18
d). 9
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