Question : If the numerator of a fraction is increased by 140% and the denominator of the fraction is decreased by 20%, the resultant fraction is $\frac{12}{7}$. Find the original fraction.
Option 1: $\frac{4}{9}$
Option 2: $\frac{4}{7}$
Option 3: $\frac{7}{6}$
Option 4: $\frac{8}{9}$
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{4}{7}$
Solution : Let $\frac{x}{y}$ be the original fraction. The fraction's numerator is increased by 140% and the denominator is decreased by 20%. $\frac{x+1.4x}{y-0.2y} = \frac{12}{7}$ ⇒$\frac{2.4x}{0.8y} = \frac{12}{7}$ ⇒$\frac{3x}{y} = \frac{12}{7}$ ⇒$\frac{x}{y} = \frac{12}{7\times 3}$ ⇒$\frac{x}{y} = \frac{4}{7}$ Hence, the correct answer is $\frac{4}{7}$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : A number is first increased by 16% and then increased by 20%. The number so obtained has now decreased by 40%. The net decrease percentage in the original number is:
Question : The arrangement of the fractions $\frac{4}{3}, -\frac{2}{9}, -\frac{7}{8}, \frac{5}{12}$ in ascending order is _____.
Question : If $\left(3 y+\frac{3}{y}\right)=8$, then find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Question : If a number is increased by 25% and the resulting number is decreased by 25%, then the percentage increase or decrease finally is:
Question : A number is first decreased by 20%. The decreased number is then increased by 20%. The resulting number is less than the original number by 20. Then the original number is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile