Question : If the radius of a sphere is doubled, then its surface area will be increased by:
Option 1: 100%
Option 2: 200%
Option 3: 300%
Option 4: 400%
Correct Answer: 300%
Solution : Given that the radius of a sphere is doubled. Let initial radius = $r_0$ We know that the surface area of a sphere = $4\pi r^2$ ⇒ Initial surface area = $4\pi r_0^2$ Now, final radius = $2r_0$ ⇒ Final surface area =$4\pi(2r_0)^2$ = $4×4\pi r_0^2$ = $16\pi r_0^2$ Increase in surface area = $16πr_0^2-4\pi r_0^2$ = $12\pi r_0^2$ Percentage increase in surface area = $\frac{12\pi r_0^2}{4\pi r_0^2}\times 100$ = 300% Hence, the correct answer is 300%.
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Question : If the radius of a sphere increases by 10%, what would be the change in the surface area of the sphere?
Option 1: 20%
Option 2: 21%
Option 3: 31%
Option 4: 25%
Question : Which of the following statements is not correct?
Option 1: For a given radius and height, a right circular cone has a lesser volume than a right circular cylinder.
Option 2: If the side of a cube is increased by 10%, the volume will increase by 33.1%.
Option 3: If the radius of a sphere is increased by 20%, the surface area will increase by 40%.
Option 4: Cutting a sphere into 2 parts does not change the total volume.
Question : When the radius of a sphere is increased by 5 cm, its surface area increases by 704 cm2. The diameter of the original sphere is _________. (Take $\pi=22 / 7$ )
Option 1: 8.2 cm
Option 2: 6.8 cm
Option 3: 5.2 cm
Option 4: 6.2 cm
Question : A sphere is of radius 5 cm. What is the surface area of the sphere?
Option 1: $100 \pi \;\mathrm{cm^2}$
Option 2: $150 \pi \;\mathrm{cm^2}$
Option 3: $200 \pi\;\mathrm{cm^2}$
Option 4: $120 \pi\;\mathrm{cm^2}$
Question : The radius of a hemisphere is twice that of a sphere. What is the ratio of the total surface area of the hemisphere and sphere?
Option 1: 3 : 1
Option 2: 12 : 1
Option 3: 4 : 1
Option 4: 6 : 1
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