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if the radius of earth shrinks by 1% without change in its mass what will be the increase in g at its surface


Aman Singh 15th Oct, 2019
Answers (2)
NAVEEN MEENA Student Expert 10th Nov, 2019

Dear Aman, the acceleration due to gravity will increase by 2%.

g=GMR^-2

On differentiating,

dg/dr= -2× g/R

Negative sign accounts for the decrease in the radius.

Now substituting dr as -1, we get dg = 2 times a quantity.

Thus accelerationddue to gravity increases by 2%.

All the best

Hope this helps

ADITYA KUMAR Student Expert 15th Oct, 2019

Hello there!

Greetings!

If acceleration due to gravity on earth(g) = G.M/R²,


then weight of the body = mg;


where G is gravitation constant, M is mass of earth and R is the radius.


Now if the radius is reduced by half it means g is reduces by 1/4th because it is inversely proportional to the square of radius.


And weight of the body is directly proportional to g, it will also reduce by a factor of 4.


Thankyou

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