Question : If the six-digit number 479xyz is exactly divisible by 7, 11, and 13, then {(y + z) ÷ x} is equal to:
Option 1: $4$
Option 2: $\frac{11}{9}$
Option 3: $\frac{7}{13}$
Option 4: $\frac{13}{7}$
Correct Answer: $4$
Solution : A 6-digit number in which a 3-digit repeat xyzxyz is divisible by 1001 and 1001 is divisible by 7, 11, and 13. ⇒ 479479 is divisible by 7, 11 and 13. Comparing 479479 with 479xyz. we get, $x = 4, y = 7 \text{ and }z = 9$ Now, {(y + z) ÷ x} = (7 + 9) ÷ 4 =$\frac{16}{4}$ = 4 Hence, the correct answer is 4.
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Question : If the six-digit number 5x2y6z is divisible by 7, 11 and 13, then the value of $(x-y+3 z)$ is:
Option 1: 7
Option 2: 4
Option 3: 0
Option 4: 9
Question : If $x+y+z=13,x^2+y^2+z^2=133$ and $x^3+y^3+z^3=847$, then the value of $\sqrt[3]{x y z}$ is:
Option 1: $8$
Option 2: $7$
Option 3: $-9$
Option 4: $-6$
Question : If the 9-digit number $72 x 8431y 4$ is divisible by 36, what is the value of $(\frac{x}{y}-\frac{y}{x})$ for the smallest possible value of $y$, given that $x$ and $y$ are natural numbers?
Option 1: $1 \frac{5}{7}$
Option 2: $2 \frac{1}{10}$
Option 3: $1 \frac{2}{5}$
Option 4: $2 \frac{9}{10}$
Question : What is $\frac{\left (x^{2}-y^{2} \right)^{3}+\left (y^{2}-z^{2} \right )^{3}+\left (z^{2}-x^{2} \right )^{3}}{\left (x-y \right)^{3}+\left (y-z \right )^{3}+\left (z-x \right)^{3}}?$
Option 1: $\frac{(x+y)(y+z)}{(x+z)}$
Option 2: $(x+y)^3(y+z)^3(z+x)^3$
Option 3: $(x+y)(y+z)(z+x)$
Option 4: $(x+y)(y+z)$
Question : If a 4-digit number x58y is exactly divisible by 9, then the least value of (x + y) is:
Option 1: 4
Option 2: 5
Option 3: 3
Option 4: 2
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