Question : If the six-digit number 5x2y6z is divisible by 7, 11 and 13, then the value of $(x-y+3 z)$ is:
Option 1: 7
Option 2: 4
Option 3: 0
Option 4: 9
Correct Answer: 7
Solution : A number divisible by 7, 11, and 13 must be of the form $abcabc$ ⇒ $5x2y6z=562562$ According to the question, which gives ⇒ $x = 6, y = 5$ and $z = 2$ So, $(x -y + 3z) = 6 - 5 + 3 × 2 = 7$ Hence, the correct answer is 7.
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