Question : If the sum of all interior angles of a regular polygon is 14 right angles, then its number of sides is:
Option 1: 8
Option 2: 9
Option 3: 7
Option 4: 6
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 9
Solution : Sum of all interior angles = $14×90^{\circ}$ = $1260^{\circ}$ Let the number of sides of the polygon be $n$. ⇒ $1260^{\circ}$ = $(n-2)×180^{\circ}$ ⇒ $(n-2)$ = $\frac{1260}{180}$ ⇒ $(n-2)$ = $7$ ⇒ $n$ = $2+7$ = $9$ Hence, the correct answer is 9.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The sum of interior angles of a regular polygon is $1440^{\circ}$. The number of sides of the polygon is:
Question : In a regular polygon if one of its internal angles is greater than the external angle by $132^\circ$, then the number of sides of the polygon is:
Question : If $\left (a+b \right):\left (b+c \right):\left (c+a \right)= 6:7:8$ and $\left (a+b+c \right) = 14,$ then value of $c$ is:
Question : If the sum of a non-zero number and thrice its reciprocal is $\frac{52}{7}$. Find the number.
Question : If A : B = 2 : 3, B : C = 6 : 7, C : D = 14 : 3, then find A : B : C : D.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile