If the thrust force on a rocket which is ejecting gases with a relative velocity of 200 is 120 .then rate of combustion?
Hello Deepali
I think, If the velocity of rocket (u) is 200m/s and force (F) is 120N, then rate of combustion of fuel is
dm/dt = F/u = 120/200 = 0.6 kg/second.
Good Luck!