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If the thrust force on a rocket which is ejecting gases with a relative velocity of 200 is 120 .then rate of combustion?


Deepali Yadav 16th Sep, 2018
Answer (1)
ruchika.chauhan Expert 6th Dec, 2018

Hello Deepali

I think, If the velocity of rocket (u) is 200m/s and force (F) is 120N, then rate of combustion of fuel is

dm/dt = F/u = 120/200 = 0.6 kg/second.

Good Luck!

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