Question : If $x^2+\frac{1}{x^2}=66$, the value of $x-\frac{1}{x}$ is:
Option 1: 10
Option 2: 8
Option 3: 9
Option 4: 6
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Answer (1)
23rd Jan, 2024
Correct Answer: 8
Solution :
Given, $x^2+\frac{1}{x^2}=66$
⇒ $x^2+\frac{1}{x^2} -2=66-2$
⇒ $x^2+\frac{1}{x^2} -2(x)(\frac{1}{x})=64$
We know that $(a-b)^2 = a^2+b^2-2ab$
So, $(x-\frac{1}{x})^2=8^2$
⇒ $(x-\frac{1}{x})=8$
Hence, the correct answer is 8.
Comments (0)
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Thank You!
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Mains Exam
Result Date:
4 Nov, 2024
- 11 Nov, 2024
Tier II
Admit Card Date:
12 Nov, 2024
- 12 Nov, 2024
Exam Date:
17 Nov, 2024
- 21 Nov, 2024
