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if the velocity of particleat x=0 is 510 and coefficient of friction variesaccording to mu =x what will be the maximum coordinate of particle will be


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shreyasahu 16th Nov, 2019
Answer (1)
Avishek Dutta 26th Dec, 2019

The acceleration is here present because of friction.

Our acceleration here would be -mu*g.

Where mu is the coefficient of friction and g is the gravitational acceleration.

Hence acceleration a=-mu*g=-xg

vdv/dx=-xg

Hence

v^2/2- 510^2/2=-g/2*x^2

Now v is zero so

510=x√g

x=510/√g=161.27



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