Question : If the volume of a sphere is 24,416.64 cm3, find its surface area (take $\pi$ = 3.14) correct to two places of decimal.
Option 1: 3069.55 cm2
Option 2: 4069.44 cm2
Option 3: 5096.66 cm2
Option 4: 6069.67 cm2
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Correct Answer: 4069.44 cm 2
Solution :
Let the radius of the sphere be $r$.
Volume of sphere = 24416.64 cm
3
$⇒\frac{4}{3} \pi r^3 $ = 24416.64 cm
3
$\therefore r$ = $\sqrt[3]{\frac{24416.64 × 3}{4 × 3.14}}$ = 18 cm
The surface area of the sphere
= $4\pi r^2$
= $4 × 3.14 × 18^2$
= $4069.44$ cm
2
Hence, the correct answer is 4069.44 cm
2
.
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