If the weightage of cbse board exam will 30% and 70% for term 1 and term2 respectively. so, How can we find the total percentage obtain ? Give example.
Answer (1)
24th May, 2022
Dear aspirant !!
Hope you are doing great ! It is easy like if you get let x marks in term 1 then find 30 percent of it by the formula ;-
30×Marks obtained / total marks . Then apply the same thing in term 2 ,just replace 30 by 70 to get 70 percent . Marks obtained = x that we supposed earlier . Now if still you find any difficulty then tell me your marks of both the terms ,i will do it for you , ask me in comment section of this question !
Hope you get it !
Thanks
2 Comments
Comments (2)
My no. Of response in term 1 was 16
And term 2 score is not declared by the school
I got total 33 marks (excluding practicals) in chemistry so how i can find term 1 marks and term 2 marks respectively
And term 2 score is not declared by the school
I got total 33 marks (excluding practicals) in chemistry so how i can find term 1 marks and term 2 marks respectively
Reply
I got 16 correct response in term 1 chemistry
And my total marks obtained excluding practicals 30 marks are 33
I am finding difficult to obtain my term 2 marks
And my total marks obtained excluding practicals 30 marks are 33
I am finding difficult to obtain my term 2 marks
