Question : If $\tan A \tan B+\frac{\cos x}{\cos A \cos B}=1$, then $x=?$
Option 1: $B$
Option 2: $A$
Option 3: $A + B$
Option 4: $A - B$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $A + B$
Solution : $\tan A \tan B+\frac{\cos x}{\cos A \cos B}=1$ ⇒ $\tan A \tan B \cos A \cos B + \cos x = \cos A \cos B$ ⇒ $\sin A \sin B + \cos x = \cos A \cos B$ ⇒ $ \cos x = \cos A \cos B - \sin A \sin B$ ⇒ $ \cos x = \cos (A+B) $ ⇒ $ x = A+B$ Hence, the correct answer is $A + B$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $2 \frac{\cos ^2 x-\sec ^2 x}{\tan ^2 x}=a+b \cos 2 x$, then $a, b=$?
Question : If $\tan \frac{A}{2}=x$, then find $x$.
Question : If $x+\frac{1}{x}=2 \cos \theta$, then $x^3+\frac{1}{x^3}=?$
Question : If $\cos x=-\frac{1}{2}, x$ lies in third quadrant, then $\tan x=?$
Question : If $\cos \theta=\frac{\sqrt{3}}{2}$, then $\tan ^2 \theta \cos ^2 \theta=?$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile