Question : If $ an \frac{\pi}{6}+\sec\frac{\pi}{6}=x$, then find $x$.
Option 1: $\sqrt{3}$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $\frac{-1}{\sqrt{3}}$
Option 4: $\frac{2}{\sqrt{3}}$

Question

Question : If $ an \frac{\pi}{6}+\sec\frac{\pi}{6}=x$, then find $x$.

Option 1: $\sqrt{3}$

Option 2: $\frac{1}{\sqrt{3}}$

Option 3: $\frac{-1}{\sqrt{3}}$

Option 4: $\frac{2}{\sqrt{3}}$

Team Careers360 · Accepted Answer

Correct Answer: $\sqrt{3}$

Solution : Given:
$ an \frac{\pi}{6}+\sec\frac{\pi}{6}=x$
⇒ $ an30^\circ+\sec30^\circ=x$
⇒ $x=\frac{1}{\sqrt{3}}+\frac{2}{\sqrt{3}}$
⇒ $x=\frac{3}{\sqrt{3}}$
$ herefore x =\sqrt{3}$
Hence, the correct answer is $\sqrt{3}$.

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Question : If $\tan \frac{\pi}{6}+\sec\frac{\pi}{6}=x$, then find $x$.Option 1: $\sqrt{3}$Option 2: $\frac{1}{\sqrt{3}}$Option 3: $\frac{-1}{\sqrt{3}}$Option 4: $\frac{2}{\sqrt{3}}$

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Question : If $\tan \frac{\pi}{6}+\sec\frac{\pi}{6}=x$, then find $x$.
Option 1: $\sqrt{3}$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $\frac{-1}{\sqrt{3}}$
Option 4: $\frac{2}{\sqrt{3}}$