Question : If $\sin ^2 heta-3 \sin heta+2=0$, then find the value of $ heta\left(0^{\circ} \leq heta \leq 90^{\circ} ight)$.
Option 1: 45°
Option 2: 0°
Option 3: 60°
Option 4: 90°

Question

Question : If $\sin ^2 heta-3 \sin heta+2=0$, then find the value of $ heta\left(0^{\circ} \leq heta \leq 90^{\circ} ight)$.

Option 1: 45°

Option 2: 0°

Option 3: 60°

Option 4: 90°

Team Careers360 · Accepted Answer

Correct Answer: 90°

Solution : Given, $\sin ^2 heta-3 \sin heta+2=0$
⇒ $(\sin heta - 1)(\sin heta- 2)=0$
⇒ $\sin heta=1$ or $\sin heta=2$
Since $\left(0^{\circ} \leq heta \leq 90^{\circ} ight)$,
⇒ $\sin heta=1$
⇒ $ heta = 90^{\circ}$
Hence, the correct answer is $90^{\circ}$.

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Question : If sin2⁡θ−3sin⁡θ+2=0, then find the value of θ(0∘≤θ≤90∘).Option 1: 45°Option 2: 0°Option 3: 60°Option 4: 90°

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Question : If $\sin^{2} θ - 3 \sin θ + 2 = 0$ , then find the value of $θ (0^{\circ} \leq θ \leq 90^{\circ})$ .
Option 1: 45°
Option 2: 0°
Option 3: 60°
Option 4: 90°