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Question : If $m+\frac{1}{m-2}=4$, then find the value of $(m-2)^2+\frac{1}{(m-2)^2}$.

Option 1: – 2

Option 2: 4

Option 3: 0

Option 4: 2


Team Careers360 19th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: 2


Solution : Given, $m+\frac{1}{m-2}=4$
⇒ $(m-2)+\frac{1}{m-2}=2$
Squaring both sides, we get:
$(m-2)^2+\frac{1}{(m-2)^2}+2(m-2)(\frac{1}{m-2})=4$
⇒ $(m-2)^2+\frac{1}{(m-2)^2}+2=4$
$\therefore(m-2)^2+\frac{1}{(m-2)^2}=2$
Hence, the correct answer is 2.

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