Question : If $\left(y+\frac{1}{y}\right)=4$, then find the value of $\left(y^6+\frac{1}{y^6}\right)$.
Option 1: 2702
Option 2: 2704
Option 3: 4096
Option 4: 2706
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Correct Answer: 2702
Solution : Given: $\left(y+\frac{1}{y}\right)=4$ Squaring both sides, we get ⇒ $\left(y+\frac{1}{y}\right)^{2}=4^{2}$ ⇒ $y^{2}+\frac{1}{y^{2}}=16-2$ ⇒ $y^{2}+\frac{1}{y^{2}}=14$ Cubing both sides, we get ⇒ $(y^{2}+\frac{1}{y^{2}})^3=14^3$ ⇒ $\left(y^6+\frac{1}{y^6}\right)+3×\left(y^2×\frac{1}{y^2}\right)×\left(y^2+\frac{1}{y^2}\right)=2744$ ⇒ $\left(y^6+\frac{1}{y^6}\right)+3×14=2744$ ⇒ $\left(y^6+\frac{1}{y^6}\right)=2744-42$ $\therefore \left(y^6+\frac{1}{y^6}\right)=2702$ Hence, the correct answer is 2702.
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