Question : If $\sin \theta-\cos \theta=0$, then find the value of $\left(\sin^3 \theta-\cos^3 \theta\right)$.
Option 1: $0$
Option 2: $2$
Option 3: $1$
Option 4: $\frac{1}{\sqrt{2}}$
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Correct Answer: $0$
Solution :
Given:
$\sin \theta - \cos \theta = 0$
⇒ $\sin \theta = \cos \theta$
So, $\sin^3 \theta - \cos^3 \theta= \cos^3 \theta - \cos^3 \theta = 0$
Hence, the correct answer is $0$.
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