Question : If $\tan \mathrm{A}=\frac{3}{4}$, then find the value of the following expression $\frac{6 \sin A}{1-\sin A}$.
Option 1: 18
Option 2: 9
Option 3: 24
Option 4: 12
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Correct Answer: 9
Solution :
Given: $\tan \mathrm{A}=\frac{3}{4}$
We know that $\tan \theta=\frac{\text{Perpendicular}}{\text{Base}}=\frac{3}{4}$
Let perpendicular = $3k$ and base = $4k$ [where $k$ is a non zero constant]
So, Hypotenuse $=\sqrt{(3k)^2+(4k)^2}=\sqrt{25k^2}=5k$
⇒ $\sin A =\frac{\text{Perpendicular}}{\text{Hypotenuse}}=\frac{3k}{5k}=\frac{3}{5}$
Now, $\frac{6 \sin A}{1-\sin A}$
$= \frac{6 ×\frac{3}{5}}{1-\frac{3}{5}}$
$= \frac{\frac{18}{5}}{\frac{2}{5}}$
$=9$
Hence, the correct answer is 9.
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