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Question : If $(x–4)(x^2+4x+16)=x^3–p$, then $p$ is equal to:

Option 1: 27

Option 2: 8

Option 3: 64

Option 4: 0


Team Careers360 13th Jan, 2024
Answer (1)
Team Careers360 19th Jan, 2024

Correct Answer: 64


Solution : Given: $(x–4)(x^2+4x+16)=x^3–p$
Formula: We know that $a^3–b^3=(a–b)(a^2+ab+b^2)$
Solution:
$x^3–p=(x–4)(x^2+4x+16)$
⇒ $x^3−p=(x^3−4^3)$
⇒ $p = 4^3$
So, $p = 64$.
Hence, the correct answer is 64.

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