Question : If $r\sin\theta=1$, $r\cos\theta=\sqrt{3}$, then the value of $(\sqrt{3}\tan\theta+1)$ is:
Option 1: $\sqrt{3}$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $1$
Option 4: $2$
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Correct Answer: $2$
Solution : Given: $r\sin\theta=1$, $r\cos\theta=\sqrt{3}$ $⇒\frac{r\sin\theta}{r\cos\theta}=\frac{1}{\sqrt{3}}$ $⇒\tan\theta=\frac{1}{\sqrt{3}}$ $⇒\sqrt{3}\tan\theta=1$ $\therefore\sqrt{3}\tan\theta+1=2$ Hence, the correct answer is $2$.
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Question : If $\sqrt{3} \tan \theta=3 \sin \theta$, then what is the value of $\sin ^2 \theta-\cos ^2 \theta$?
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