Question : If $x=\sqrt[3]{x^{2}+11} –2$, then the value of $(x^3+5x^2+12x)$ is:
Option 1: 0
Option 2: 3
Option 3: 7
Option 4: 11
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 3
Solution : Given: $x=\sqrt[3]{x^{2}+11} –2$ ⇒ $x+2=\sqrt[3]{x^{2}+11}$ ⇒ $(x+2)^3=(x^{2}+11)$ (Taking cube on both sides) ⇒ $x^3+6x^2+12x+8=x^{2}+11$ ⇒ $x^3+5x^2+12x=3$ Hence, the correct answer is 3.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If $x = \sqrt[3]{5} + 2$, then the value of $x^3-6x^2+12x-13$ is:
Question : If $\sqrt{5x-6}+\sqrt{5x+6}=6$, then what is the value of $x$?
Question : If $x=\sqrt{–\sqrt{3}+\sqrt{3+8 \sqrt{7+4 \sqrt{3}}}}$ where $x > 0$, then the value of $x$ is equal to:
Question : If $x^2-\sqrt{7} x+1=0$, then what is the value of $x^5+\frac{1}{x^5} ?$
Question : If $(x+\frac{1}{x})=–2$, then the value of $(x^7+\frac{1}{x^7})$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile