Question : If $2\sin(\frac{\pi x}{2})=x^2+\frac{1}{x^2}$, then the value of $(x-\frac{1}{x})$ is:
Option 1: $–1$
Option 2: $2$
Option 3: $1$
Option 4: $0$
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: $0$
Solution : Given: $2\sin(\frac{\pi x}{2})=x^2+\frac{1}{x^2}$ ⇒ $2\sin(\frac{\pi x}{2})=(x - \frac{1}{x})^2 + 2$ Since $\sin\theta$ has a maximum value equal to 1, ⇒ $(x - \frac{1}{x})$ = 0 Hence, the correct answer is 0.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If $\tan x = \frac{7}{5}$, the value of $\frac{9 \sin x – \frac{42}{5} \cos x}{15 \sin x + 21 \cos x}$ is:
Question : If $(x+\frac{1}{x})^{2}=3$, then the value of $(x^{3}+\frac{1}{x^{3}})$ is:
Question : If $x^{2}+\frac{1}{x^{2}} = 98(x>0)$, then the value of $x^{3}+\frac{1}{x^{3}}$ is:
Question : If $(x+\frac{1}{x})=–2$, then the value of $(x^7+\frac{1}{x^7})$ is:
Question : If $x+ \frac{1}{x} =2$, then the value of $({x}^{99}+ \frac{1}{x^{99}} –2)$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile