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Question : If $\cos\left(40^\circ+x\right)=\sin 30^\circ$, then the value of $x$ is:

Option 1: $22^\circ$

Option 2: $20^\circ$

Option 3: $19^\circ$

Option 4: $23^\circ$


Team Careers360 18th Jan, 2024
Answer (1)
Team Careers360 24th Jan, 2024

Correct Answer: $20^\circ$


Solution : $\cos \left(40^\circ+x\right)=\sin 30^\circ$ ....(1)
Now we know that $\sin(90^\circ -x)= \cos x^\circ$
$\therefore$ Equation (1) becomes
⇒ $\cos \left(40^\circ+x\right)=\sin (90^\circ-60^\circ)$
⇒ $\cos \left(40^\circ+x\right)=\cos 60^\circ$
⇒ $(40^\circ+x) = 60^\circ$
$\therefore x=20^\circ$
Hence, the correct answer is $20^\circ$.

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