Question : If $\tan A=\frac{3}{8}$, then the value of $\frac{3 \sin A+2 \cos A}{3 \sin A-2 \cos A}$ is:
Option 1: $-\frac{13}{25}$
Option 2: $-\frac{25}{7}$
Option 3: $\frac{25}{8}$
Option 4: $\frac{13}{21}$
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Correct Answer: $-\frac{25}{7}$
Solution : Given: $\frac{3 \sin A+2 \cos A}{3 \sin A-2 \cos A}$ Dividing both numerator and denominator by $\cos A$, = $\frac{3 \tan A+2}{3 \tan A-2}$ = $\frac{3(\frac{3}{8})+2}{3(\frac{3}{8})-2}$ = $-\frac{25}7$ Hence, the correct answer is $-\frac{25}7$.
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