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Question : If $\tan A=\frac{3}{8}$, then the value of $\frac{3 \sin A+2 \cos A}{3 \sin A-2 \cos A}$ is:

Option 1: $-\frac{13}{25}$

Option 2: $-\frac{25}{7}$

Option 3: $\frac{25}{8}$

Option 4: $\frac{13}{21}$


Team Careers360 6th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: $-\frac{25}{7}$


Solution : Given: $\frac{3 \sin A+2 \cos A}{3 \sin A-2 \cos A}$
Dividing both numerator and denominator by $\cos A$,
= $\frac{3 \tan A+2}{3 \tan A-2}$
= $\frac{3(\frac{3}{8})+2}{3(\frac{3}{8})-2}$
= $-\frac{25}7$
Hence, the correct answer is $-\frac{25}7$.

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