Question : If $\frac{(3 \sin \theta-\cos \theta)}{(\cos \theta+\sin \theta)}=1$, then the value of $\cot \theta$ is:
Option 1: 3
Option 2: 0
Option 3: 1
Option 4: 2
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Correct Answer: 1
Solution : $\frac{(3 \sin \theta-\cos \theta)}{(\cos \theta+\sin \theta)}=1$ Divide the numerator and denominator by $\sin \theta$. ${(3 -\cot \theta)}={(\cot \theta+ 1)}$ ⇒ $2\cot \theta = 2$ ⇒ $\cot \theta=1$ Hence, the correct answer is 1.
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Question : If $\sin \theta-\cos \theta=0$, then find the value of $\left(\sin^3 \theta-\cos^3 \theta\right)$.
Question : If $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}=\frac{3}{2}$, then the value of $\sin ^4 \theta-\cos ^4 \theta$ is:
Question : If $x\sin^{3}\theta +y\cos^{3}\theta=\sin\theta\cos\theta$ and $x\sin\theta-y\cos\theta=0$, then the value of $\left ( x^{2}+y^{2} \right )$ equals:
Question : If $\sin \theta+\sin ^2 \theta=1$, then the value of $\cos ^2 \theta+\cos ^4 \theta$ is equal to:
Question : If $\tan\theta=1$, then the value of $\frac{8\sin\theta\:+\:5\cos\theta}{\sin^{3}\theta\:–\:2\cos^{3}\theta\:+\:7\cos\theta}$ is:
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