Question : If $x+\frac{1}{x}=2$, then the value of $x^{11}+\frac{1}{x^{20}}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 7

Question

Question : If $x+\frac{1}{x}=2$, then the value of $x^{11}+\frac{1}{x^{20}}$ is:

Option 1: 0

Option 2: 1

Option 3: 2

Option 4: 7

Team Careers360 · Accepted Answer

Correct Answer: 2

Solution : Given, $x+\frac{1}{x}=2$
⇒ $x^2+1=2x$
⇒ $x^2+1-2x=0$
⇒ $(x-1)^2=0$
⇒ $x-1=0$
$ herefore x=1$
Consider, $x^{11}+\frac{1}{x^{20}}$
= $1^{11}+\frac{1}{1^{20}}$
= $1+1$
= $2$
Hence, the correct answer is 2.

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Question : If x+1x=2, then the value of x11+1x20 is:Option 1: 0Option 2: 1Option 3: 2Option 4: 7

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Question : If $x + \frac{1}{x} = 2$ , then the value of $x^{11} + \frac{1}{x^{20}}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 7