Question : If $\sin \theta=\frac{1}{2}$, then the value of $\left(3 \cos \theta-4 \cos ^3 \theta\right)$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: – 1
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Correct Answer: 0
Solution : Given, $\sin \theta=\frac{1}{2}$ ⇒ $\theta = 30^\circ$ Now, $\left(3 \cos \theta-4 \cos ^3 \theta\right)=-\cos 3\theta$ ⇒ $\left(3 \cos \theta-4 \cos ^3 \theta\right)=-\cos 90^\circ$ ⇒ $\left(3 \cos \theta-4 \cos ^3 \theta\right)=0$ Hence, the correct answer is 0.
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Question : If $\sin \theta-\cos \theta=0$, then find the value of $\left(\sin^3 \theta-\cos^3 \theta\right)$.
Question : If $x\sin^{3}\theta +y\cos^{3}\theta=\sin\theta\cos\theta$ and $x\sin\theta-y\cos\theta=0$, then the value of $\left ( x^{2}+y^{2} \right )$ equals:
Question : If $\tan \theta=\frac{4}{3}$, then the value of $\frac{3\sin \theta+ 2\cos \theta}{3\sin \theta – 2 \cos \theta}$ is:
Question : If $\tan\theta=1$, then the value of $\frac{8\sin\theta\:+\:5\cos\theta}{\sin^{3}\theta\:–\:2\cos^{3}\theta\:+\:7\cos\theta}$ is:
Question : If $\frac{(3 \sin \theta-\cos \theta)}{(\cos \theta+\sin \theta)}=1$, then the value of $\cot \theta$ is:
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