Question : If $x+\frac{1}{x}=3$, then the value of $x^5+\frac{1}{x^5}$ is:
Option 1: 322
Option 2: 126
Option 3: 123
Option 4: 113
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Correct Answer: 123
Solution : Given: $x+\frac{1}{x}=3$ $x^2+\frac{1}{x^2}=(x+\frac{1}{x})^2-2=3^2-2=7$. Similarly, $x^3+\frac{1}{x^3}=(x+\frac{1}{x})^3-3×x×\frac{1}{x}(x+\frac{1}{x})=3^3-3\times 3=18$. Now, $x^5+\frac{1}{x^5}=(x^2+\frac{1}{x^2})(x^3+\frac{1}{x^3})-(x+\frac{1}{x})$ Putting the values of $x^2+\frac{1}{x^2}$ and $x^3+\frac{1}{x^3}$, we get: $\therefore x^5+\frac{1}{x^5}=7\times 18-3=123$ Hence, the correct answer is 123.
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