Question : If $\sec heta+ an heta=3$, then the value of $\sec heta$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{5}{3}$

Question

Question : If $\sec heta+ an heta=3$, then the value of $\sec heta$ is:

Option 1: $\frac{4}{3}$

Option 2: $\frac{3}{4}$

Option 3: $\frac{3}{5}$

Option 4: $\frac{5}{3}$

Team Careers360 · Accepted Answer

Correct Answer: $\frac{5}{3}$

Solution : Given: The value of the trigonometric equation is $\sec heta+ an heta=3$.
We know that if $\sec heta+ an heta=x$. Then, $\sec heta– an heta=\frac{1}{x}$.
$\sec heta+ an heta=3$ (equation 1)
⇒ $\sec heta– an heta=\frac{1}{3}$ (equation 2)
Adding equation 1 and equation 2,
$\sec heta+ an heta+\sec heta– an heta=3+\frac{1}{3}$
⇒ $2\sec heta=\frac{3 imes 3 +1}{3}$
⇒ $2\sec heta=\frac{10}{3}$
⇒ $\sec heta=\frac{5}{3}$
Hence, the correct answer is $\frac{5}{3}$.

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Question : If sec⁡θ+tan⁡θ=3, then the value of sec⁡θ is:Option 1: 43Option 2: 34Option 3: 35Option 4: 53

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Question : If $\sec θ + \tan θ = 3$ , then the value of $\sec θ$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{5}{3}$