Question : If $\frac{x}{4 y}=\frac{3}{4}$ then, the value of $\frac{2 x+3 y}{x–2 y}$ is:
Option 1: 7
Option 2: 9
Option 3: 6
Option 4: 8
Correct Answer: 9
Solution : Given: $\frac{x}{4 y}=\frac{3}{4}$ ⇒ $x=3y$ The value of the expression $\frac{2x+3y}{x–2y}=\frac{2\times 3y+3 y}{3y–2 y}=\frac{6y+3y}{y}=\frac{9y}{y}=9$ Hence, the correct answer is 9.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : If $x^2+8 y^2+12 y-4 x y+9=0$, then the value of $(7 x+8 y)$ is:
Question : If $x+y+z=13,x^2+y^2+z^2=133$ and $x^3+y^3+z^3=847$, then the value of $\sqrt[3]{x y z}$ is:
Question : If $(\frac{x}{y})^{5a-3}=(\frac{y}{x})^{17-3a}$, then what is the value of $a$?
Question : If $x^4+x^2 y^2+y^4=133$ and $x^2-x y+y^2=7$, then what is the value of $xy$?
Question : If $x^2 = y+z$, $y^2=z+x$, $z^2=x+y$, then the value of $\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile