Question : If $(\sqrt 3 +1)^{2}=x+\sqrt 3 y$, then the value of $(x+y)$ is:
Option 1: 2
Option 2: 4
Option 3: 6
Option 4: 8
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Answer (1)
25th Jan, 2024
Correct Answer: 6
Solution :
Given: $(\sqrt{3}+1)^2 = x+\sqrt{3}y$
⇒ $(3+1+2\sqrt{3})=x+\sqrt{3}y$
⇒ $(4+2\sqrt{3})=x+\sqrt{3}y$
Comparing both sides, we get $x=4$ and $y =2$.
Thus, $(x+y)=(4+2)=6$
Hence, the correct answer is 6.
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