Question : If $\frac{a}{b}+\frac{b}{a}=2$, then the value of $(a-b)$ is:
Option 1: 1
Option 2: 2
Option 3: –1
Option 4: 0
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 0
Solution : Given: $\frac{a}{b}+\frac{b}{a}=2$ ⇒ $\frac{a^2+b^2}{ab} = 2$ ⇒ $a^2+b^2-2ab = 0$ ⇒ $(a-b)^2 = 0$ ⇒ $(a-b) = 0$ Hence, the correct answer is 0.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $\frac{1}{a}–\frac{1}{b}=\frac{1}{a–b}$, then the value of $a^{3}+b^{3}$ is:
Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Question : If $\frac{x}{3}+\frac{3}{x}=1$, then the value of $x^3$ is:
Question : If $a^3+b^3=9$ and $a+b=3$, then the value of $\frac{1}a+\frac{1}b$ is:
Question : If $a+\frac{1}{a}=\sqrt{3}$, then the value of $a^{18}+a^{12}+a^{6}+1$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile