Question : If $\left (4x+\frac{1}{x} \right)=5,x\neq 0,$ then the value of $\frac{5x}{4x^{2}+10x+1}$ is:
Option 1: $\frac{1}{2}$
Option 2: $\frac{1}{3}$
Option 3: $\frac{2}{3}$
Option 4: $3$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: $\frac{1}{3}$
Solution :
Given: $(4x+\frac{1}{x})=5$
⇒ $\frac{4x^{2}+1}{x}=5$
⇒ $4x^{2}+1=5x$
⇒ $4x^{2}=5x-1$
Now, putting the value of $4x^{2}$ in $\frac{5x}{4x^{2}+10x+1}$
$=\frac{5x}{5x–1+10x+1}=\frac{5x}{15x}=\frac{1}{3}$
Hence, the correct answer is $\frac{1}{3}$.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
