Question : If $\sec( 4x-50°)=\operatorname{cosec}( 50°-x)$, then the value of $x$ is:
Option 1: 45°
Option 2: 90°
Option 3: 30°
Option 4: 60°
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Correct Answer: 30°
Solution :
Given: $\sec( 4x-50°)=\operatorname{cosec}( 50°-x)$
⇒ $\sec( 4x-50° )=\sec(90°-( 50°-x)$
⇒ $(4x-50°)=(90°-( 50°-x)$
⇒ $4x-50°=90°-50°+x$
⇒ $3x=90°$
⇒ $x=30°$
Hence, the correct answer is 30°.
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