Question : If $(x-5)^2+(y-2)^2+(z-9)^2=0$, then value of $(x+y-z)$ is:
Option 1: 16
Option 2: –1
Option 3: –2
Option 4: 12
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Answer (1)
21st Jan, 2024
Correct Answer: –2
Solution :
Given:
$(x-5)^2+(y-2)^2+(z-9)^2=0$
So, $x=5, y=2, z=9$
Therefore, $x+y-z = (5+2-9) = -2$
Hence, the correct answer is –2.
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