Question : If $(x - 5)^{2} + (y - 2)^{2} + (z - 9)^{2} = 0$ , then value of $(x + y - z)$ is:
Option 1: 16
Option 2: –1
Option 3: –2
Option 4: 12

Question

Question : If $x + y + z = 0$ and $x^{2} + y^{2} + z^{2} = 40$ , then what is the value of $x y + y z + z x ?$
Option 1: –20
Option 2: 5
Option 3: –5
Option 4: –10

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Answer 1

Correct Answer: –2

Solution : Given:
$(x - 5)^{2} + (y - 2)^{2} + (z - 9)^{2} = 0$
So, $x = 5, y = 2, z = 9$
Therefore, $x + y - z = (5 + 2 - 9) = - 2$
Hence, the correct answer is –2.

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Question : If (x−5)2+(y−2)2+(z−9)2=0, then value of (x+y−z) is:Option 1: 16Option 2: –1Option 3: –2Option 4: 12

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Question : If $(x - 5)^{2} + (y - 2)^{2} + (z - 9)^{2} = 0$ , then value of $(x + y - z)$ is:
Option 1: 16
Option 2: –1
Option 3: –2
Option 4: 12