Question : If $2\cot x=5$, then what is $\frac{2 \cos x-\sin x}{2 \cos x+\sin x}$ equal to?
Option 1: $\frac{3}{4}$
Option 2: $\frac{1}{3}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{2}{3}$
Solution : $2\cot x=5$ Or, $\cot x = \frac{5}{2}$ Given expression: $\frac{2 \cos x-\sin x}{2 \cos x+\sin x}$ Dividing the numerator and the denominator by $\sin x $, The expression becomes, $\frac{2\cot x - 1}{2\cot x + 1} = \frac{2\times\frac{5}{2} - 1}{2\times\frac{5}{2}+1}=\frac{5-1}{5+1}=\frac{4}{6} = \frac{2}{3}$ Hence, the correct answer is $\frac{2}{3}$.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : If $\frac{\sin x-\cos x}{\sin x+\cos x}=\frac{2}{5}$, then the value of $\frac{1+\cot ^2 x}{1-\cot ^2 x}$ is:
Question : If $\tan x = \frac{7}{5}$, the value of $\frac{9 \sin x – \frac{42}{5} \cos x}{15 \sin x + 21 \cos x}$ is:
Question : If $\sin (x+y) = \cos (x–y)$, then the value of $\cos^2 x$ is:
Question : If $x\sin^{3}\theta +y\cos^{3}\theta=\sin\theta\cos\theta$ and $x\sin\theta-y\cos\theta=0$, then the value of $\left ( x^{2}+y^{2} \right )$ equals:
Question : $\frac{\cos A}{1-\tan A}+\frac{\sin A}{1-\cot A}=$___________.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile