Question : If $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}=3$, then what is the value of $(x+y+z)^3$?
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
Answer (1)
25th Jan, 2024
Correct Answer: 0
Solution :
Given:$\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}=3$
We know the identity, if $(x+y+z)=0$, then $(x^3+y^3+z^3)=3xyz$
Take the LCM of the given expression, we get–
$\frac{x^3+y^3+z^3}{xyz}=3$
${x^3+y^3+z^3}=3(xyz)$
So, $(x+y+z)=0$
The value of $(x+y+z)^3=0$
Hence, the correct answer is 0.
Comments (0)
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Get Updates Brochure
Thank You!
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Application Date:
9 Dec, 2024
- 30 Dec, 2024
Admit Card Date:
28 Dec, 2024
- 16 Jan, 2025
Application Date:
2 Dec, 2024
- 31 Dec, 2024
Admit Card Date:
23 Dec, 2024
- 5 Jan, 2025
Application Date:
15 Dec, 2024
- 5 Jan, 2025
