Question : If $\frac{x}{2}-\frac{\left [4\left (\frac{15}{2}-\frac{x}{3} \right ) \right ]}{3} = –\frac{x}{18}$ then what is the value of $x$?
Option 1: –$10$
Option 2: $\frac{9}{8}$
Option 3: $10$
Option 4: $–\frac{9}{8}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $10$
Solution : $\frac{x}{2}–\frac{\left [4\left ( \frac{15}{2}-\frac{x}{3} \right ) \right ]}{3} = –\frac{x}{18}$ ⇒ $\frac{x}{2}+\frac{x}{18} = \frac{\left [ 4\left ( \frac{15}{2}-\frac{x}{3} \right )\right ]}{3}$ ⇒ $\frac{20x}{36} = \frac{30–\frac{4x}{3}}{3}$ ⇒ $\frac{5x}{9} = 10-\frac{4x}{9}$ ⇒ $\frac{5x}{9}+\frac{4x}{9} = 10$ $\therefore x =10$ Hence, the correct answer is $10$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $x^{2} -3x +1=0$, then the value of $\frac{\left(x^4+\frac{1}{x^2}\right)}{\left(x^2+5 x+1\right)}$ is:
Question : The value of $15 \div 8-\frac{5}{4}$ of $\left(\frac{8}{3} \times \frac{9}{16}\right)+\left(\frac{9}{8} \times \frac{3}{4}\right)-\left(\frac{5}{32} \div \frac{5}{7}\right)+\frac{3}{8}$ is:
Question : If $2\left [x^{2} +\frac{1}{x^{2}}\right]-2\left [x-\frac{1}{x} \right]-8=0$, what are the two values of $\left (x-\frac{1}{x} \right)\;$?
Question : If ${\left(x-\frac{1}{x}\right)=\sqrt{6}}$ and $x > 1$, what is the value of ${\left(x^8-\frac{1}{x^8}\right)}$?
Question : If $\frac {x^2+3x+1}{x^2–3x+1}=\frac{1}{2 }$, then the value of $(x+\frac{1}{x})$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile