Question : If $a+b+c=16,ab+bc+ca=81$, then what is the value of $a^2+b^2+c^2$?
Option 1: 94
Option 2: 98
Option 3: 89
Option 4: 87
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Correct Answer: 94
Solution :
Given:
$a+b+c=16, ab+bc+ca=81$
Now, $a^2+b^2+c^2$
= $(a+b+c)^2-2(ab+bc+ca)$
= $16^2-2×81$
= $256-162$
= $94$
Hence, the correct answer is 94.
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