Question : If $\sin \theta = \frac{3}{11}$, then what is the value of $\cot \theta$?
Option 1: $\frac{3 \sqrt{7}}{11}$
Option 2: $\frac{4 \sqrt{7}}{11}$
Option 3: $\frac{4 \sqrt{7}}{3}$
Option 4: $\frac{3 \sqrt{7}}{28}$
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Correct Answer: $\frac{4 \sqrt{7}}{3}$
Solution : Given, $\sin \theta=\frac{3}{11}$ We know, $\sin\theta = \frac{\text{Perpendicular}}{\text{Hypotenuse}}$ Using Pythagoras theorem, we get, $\small (\text{Hypotenuse})^2 = (\text{Base})^2 + (\text{Perpendicular})^2$ Let base = $b$ ⇒ $11^2 = b^2 + 3^2$ ⇒ $b^2 = 121 - 9$ ⇒ $b = \sqrt{112} = 4\sqrt7$ ⇒ $\cot\theta = \frac{\text{base}}{\text{perpendicular}} = \frac{4\sqrt7}{3}$ Hence, the correct answer is $\frac{4\sqrt7}{3}$.
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Question : If $\sec \theta+\tan \theta=\frac{1}{\sqrt{3}}$, then the positive value of $\cot \theta+\cos \theta$ is:
Option 1: $\frac{3 \sqrt{3}}{2}$
Option 2: $\frac{\sqrt{3}}{2}$
Option 3: $\frac{2}{3 \sqrt{3}}$
Option 4: $\frac{2}{\sqrt{3}}$
Question : If $\sin\theta+\cos\theta=\sqrt{2}\cos\theta$, then the value of $\cot\theta$ is:
Option 1: $\sqrt{2}+1$
Option 2: $\sqrt{2}-1$
Option 3: $\sqrt{3}-1$
Option 4: $\sqrt{3}+1$
Question : If $\theta$ is an acute angle and $\sin \theta \cos \theta=2 \cos ^3 \theta-\frac{1}{4} \cos \theta$, then the value of $\sin \theta$ is:
Option 1: $\frac{\sqrt{15}-1}{8}$
Option 2: $\frac{\sqrt{15}-1}{4}$
Option 3: $\frac{\sqrt{15}+1}{4}$
Option 4: $\frac{\sqrt{15}-1}{2}$
Question : If $\operatorname{cosec} \theta-\cot \theta=\frac{7}{2}$, then the value of $\operatorname{cosec} \theta$ will be:
Option 1: $\frac{49}{28}$
Option 2: $\frac{21}{28}$
Option 3: $\frac{47}{28}$
Option 4: $\frac{53}{28}$
Question : If $\sin \theta \cos \theta=\frac{1}{\sqrt{3}}$ then the value of $\left(\sin ^4 \theta+\cos ^4 \theta\right)$ is:
Option 1: $1$
Option 2: $\frac{5}{3}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{1}{3}$
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